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What is the missing exponent that would make this equation true? ◂=▸ ◂...▸k−5⋅ k2 kx =◂◽˙▸(k0)−2(1 point) Responses x = 2 x = 2 x = -3 x = -3 x = 0 x = 0 x = -5
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The missing exponent that would make this equation true is x = -5.
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