Use the image to answer the question.
An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ?
(1 point)
Responses
(10, 4)
left parenthesis 10 comma 4 right parenthesis
(2, 12)
left parenthesis 2 comma 12 right parenthesis
(2, 0)
left parenthesis 2 comma 0 right parenthesis
(6, 0)
To translate the figure 6 units down and 2 units to the right, you would subtract 6 from the y-coordinate and add 2 to the x-coordinate.
The coordinates of P are (4, 6). After the translation, the new coordinates of P' would be:
x-coordinate: 4 + 2 = 6
y-coordinate: 6 - 6 = 0
So, the coordinates of P' are (6, 0).