Given point A (2,4) on the triangle quadrant I where is the new point if the triangle is rotated 270 degrees counterclockwise
To rotate a point counterclockwise around the origin by 270 degrees, we can use the following rotation formula:
x' = x * cos(theta) - y * sin(theta)
y' = x * sin(theta) + y * cos(theta)
In this case, theta is 270 degrees, which is equivalent to -90 degrees.
Plugging in the given coordinates for point A (x = 2, y = 4), we can calculate the new coordinates:
x' = 2 * cos(-90) - 4 * sin(-90) = 2 * 0 - 4 * (-1) = 4
y' = 2 * sin(-90) + 4 * cos(-90) = 2 * (-1) + 4 * 0 = -2
Therefore, the new point after rotating point A (2,4) 270 degrees counterclockwise is (4, -2).