Sides of Similar Figures Practice
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Question
Use the image to answer the question.
An illustration shows two quadrilaterals, one big and one small. In the small quadrilateral, one side measures 2 and its opposite side measures 5. In the big quadrilateral, the side corresponding to 2 in the small quadrilateral measures 3.6 and the side corresponding to 5 measures x.
The two quadrilaterals are similar. What is the value of x ?
(1 point)
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To find the value of x, we can set up a proportion using the corresponding sides of the two quadrilaterals:
2/5 = 3.6/x
To solve for x, we can cross-multiply:
2x = 3.6 * 5
2x = 18
Divide both sides of the equation by 2:
x = 9
Therefore, the value of x is 9.
To find the width of the larger rectangle, we can set up a proportion using the lengths of the two rectangles:
3.4/5.7 = 17/x
To solve for x, we can cross-multiply:
3.4x = 17 * 5.7
3.4x = 96.9
Divide both sides of the equation by 3.4:
x = 96.9/3.4
x ≈ 28.5
Therefore, the width of the larger rectangle is approximately 28.5 ft.
A rectangle has a length of 3.4 ft. and a width of 5.7 ft. A larger similar rectangle has a length of 17 ft. What is the width of the larger rectangle?(1 point)
ft.
A right isosceles triangle has side lengths of 13.2, 13.2, and 18.6 meters. What is the hypotenuse of a similar triangle with legs 4.4 meters in length?(1 point)
meters
Since the triangle is right isosceles, it means that the two legs of the triangle are congruent.
To find the hypotenuse of a similar triangle, we can set up a proportion using the corresponding side lengths:
13.2/13.2 = x/4.4
To solve for x, we can cross-multiply:
13.2 * 4.4 = 13.2 * x
57.6 = 13.2x
Divide both sides of the equation by 13.2:
x ≈ 4.36
Therefore, the hypotenuse of the similar triangle with legs 4.4 meters in length is approximately 4.36 meters.