Calculate the number of miles of silver nitrate : CaCl2 + 2AgNO3 → Ca(NO3)2 + 2AgCl
To calculate the number of miles of silver nitrate (AgNO3), we need to know the amount of silver nitrate in moles and the molar mass of silver nitrate.
The balanced chemical equation is:
CaCl2 + 2AgNO3 → Ca(NO3)2 + 2AgCl
From the equation, we can see that 2 moles of AgNO3 react with 1 mole of CaCl2 to produce 2 moles of AgCl. This means that the ratio of AgNO3 to AgCl is 1:2.
Let's assume we have X moles of AgNO3.
Since the ratio of AgNO3 to AgCl is 1:2, the number of moles of AgCl produced will also be 2X.
To calculate the molar mass of AgNO3, we add the atomic masses of each element in the compound:
Ag (Silver) = 107.87 g/mol
N (Nitrogen) = 14.01 g/mol
O (Oxygen) = 16.00 g/mol
AgNO3 = (1 * Ag) + (1 * N) + (3 * O)
AgNO3 = (1 * 107.87) + (1 * 14.01) + (3 * 16.00)
AgNO3 = 107.87 + 14.01 + 48.00
AgNO3 = 169.88 g/mol
Now, to calculate the number of miles of AgNO3 (X), we need to convert its mass to miles. Assuming the density of silver nitrate is 4.35 g/cm³, we can use the following conversion factors:
1 g = 1 cm³
1 cm³ = 1 mL
1 L = 1000 mL
1 mile = 1609.34 meters = 1000 meters/km = 100 cm/m = 1,000,000 cm/km
Let's convert the mass of AgNO3 in grams to miles.
X moles of AgNO3 × Molar mass of AgNO3 (g/mol) = Mass of AgNO3 (grams)
X grams of AgNO3 × (1 mile / 4.35 g) × (1/1000) × (1/100) × (1/1000) × (1/100) = X miles
Substituting the values:
X grams of AgNO3 × (1 mile / 4.35 g) × (1/1000) × (1/100) × (1/1000) × (1/100) = X miles
X miles = (X / 4.35) * (1/1,000,000)
Therefore, the number of miles of silver nitrate will be (X / 4.35) * (1/1,000,000) miles.