A model train transformer delivers 14v to the engine. If the input voltage to the transformer is 100v and primary coil contains 400turns, howany turns on the 14v secondary couo? If the transformer is ideal and the train draws 4 A, what is the current drawn from the circuit
To determine the number of turns on the 14V secondary coil, we can use the formula for voltage transformation in a transformer:
Vp / Vs = Np / Ns
where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of turns on the primary coil, and Ns is the number of turns on the secondary coil.
Given:
Vp = 100V
Vs = 14V
Np = 400 turns
Substituting these values into the formula, we can solve for Ns:
100 / 14 = 400 / Ns
14 * 400 = 100 * Ns
5600 = 100 * Ns
Ns = 5600 / 100
Ns = 56 turns
Therefore, the 14V secondary coil has 56 turns.
To calculate the current drawn from the circuit, we can use the formula for current transformation in a transformer:
Ip / Is = Ns / Np
where Ip is the primary current, Is is the secondary current, Ns is the number of turns on the secondary coil, and Np is the number of turns on the primary coil.
Given:
Is = 4A
Ns = 56 turns
Np = 400 turns
Substituting these values into the formula, we can solve for Ip:
Ip / 4 = 56 / 400
Ip = 4 * 56 / 400
Ip = 0.56 A
Therefore, the current drawn from the circuit is 0.56 A.