3. The cruise ship in question 2 is travelling with a velocity of 2.8 m/s [N] off the
coast of British Columbia, in a place where the ocean current has a velocity rela-
tive to the coast of 2.4 m/s [N]. Determine the velocity of the group of tourists in
2(c) relative to the coast.
To determine the velocity of the group of tourists relative to the coast, we can use vector addition.
The velocity of the cruise ship relative to the coast is given as 2.8 m/s [N]. This means that the cruise ship is moving northward at a speed of 2.8 m/s.
The velocity of the ocean current relative to the coast is given as 2.4 m/s [N]. This means that the ocean current is also moving northward at a speed of 2.4 m/s.
To find the velocity of the group of tourists relative to the coast, we add the velocities of the cruise ship and the ocean current. Since they are both moving in the same direction (northward), we can simply add the magnitudes of the velocities:
Magnitude of velocity of the group of tourists = Magnitude of velocity of cruise ship + Magnitude of velocity of ocean current
= 2.8 m/s + 2.4 m/s
= 5.2 m/s
Therefore, the velocity of the group of tourists relative to the coast is 5.2 m/s [N]. This means that the group of tourists is moving northward at a speed of 5.2 m/s.