The perimeter of a rectangle is 15x + 17y. If the length is 7/2x + 7y then find the width of the rectangle.
4x + 3/2y
8x + 3y
8x + 10y
4x + 3y
To find the width of the rectangle, we need to subtract the length from the perimeter.
The length is given as 7/2x + 7y.
The perimeter is given as 15x + 17y.
Subtracting the length from the perimeter gives:
(15x + 17y) - (7/2x + 7y)
To subtract the expressions, we combine like terms. Note that we need to distribute the negative sign when subtracting (7/2x + 7y).
(15x + 17y) - (7/2x + 7y) =
15x + 17y - 7/2x - 7y
Now, let's combine like terms by adding or subtracting coefficients of similar variables (x and y).
(15x - 7/2x) + (17y - 7y) =
(30/2x - 7/2x) + (17y - 7y) =
(23/2x) + (10y)
So, the width of the rectangle is 23/2x + 10y, which can be simplified as:
(23/2)x + 10y
= 23/2x + 10y
= (23/2)x + 10y
= 23x/2 + 10y
= 11.5x + 10y
Therefore, the width of the rectangle is 11.5x + 10y, or in simplified form, 23/2x + 10y.
4x + 3/2y
8x + 3y
8x + 10y
4x + 3y
(answer choices)
The correct answer is:
4x + 3y