Given that ∠XQR = 180° and ∠LQM = 180°, which equation could be used to solve problems involving the relationships between ∠XQM and ∠RQM?
Responses
A 180 + (3a + 39) = (136 − 2a)180 + (3a + 39) = (136 − 2a)
B (3a + 39) − 180 = (136 − 2a)(3a + 39) − 180 = (136 − 2a)
C (136 − 2a) − (3a + 39) = 180(136 − 2a) − (3a + 39) = 180
D (136 − 2a) + (3a + 39) = 180(136 − 2a) + (3a + 39) = 180
E 360 − (3a + 39) = (136 − 2a)
The correct equation to solve problems involving the relationships between ∠XQM and ∠RQM would be:
D (136 − 2a) + (3a + 39) = 180