Equivalent to (21x^-2)^0? A. (21x^12y)^1 b. 0x^2•21x^4 c. 3x^2•(1/7)x^-2 d. 7x^2/7x^2
The answer is D. 7x^2/7x^2.
When any base is raised to the power of 0, the result is always 1. Therefore, (21x^-2)^0 is equal to 1.
Answer A is incorrect because it has a different base (y) and the exponent and constant do not match the given expression.
Answer B is incorrect because multiplying x^2 by x^4 would result in x^6, not x^0.
Answer C is incorrect because multiplying 3x^2 by (1/7)x^-2 would result in a different expression than the given expression.
Answer D is correct because 7x^2/7x^2 is equivalent to 1, which is the value of (21x^-2)^0.