Which missing exponent would make this expression true?
K^-5 * k^2 /k^x = (k^0)^-2
X=0
X=-3
X=-5
X=2
To solve this problem, we can simplify both sides of the equation.
On the left side, we have K^-5 * k^2 /k^x. Using the properties of exponents, we can combine the terms and write this expression as K^-5 * k^(2-x).
On the right side, we have (k^0)^-2. Any number raised to the power of 0 is equal to 1, so this can be simplified to 1^-2, which is equal to 1.
Since the equation is now K^-5 * k^(2-x) = 1, we can see that in order for the equation to be true, the value of (2 - x) should be equal to 0. Therefore, x must be equal to 2.
So the missing exponent that would make the expression true is x = 2.