2 Find the axis of symmetry, the vertex, and
the y-intercept for the following quadratic
equation:
π¦ = π₯squared + 2π₯ β 2
To find the axis of symmetry, we can use the formula:
π₯ = -π/2π
In this case, π = 1 and π = 2. Plugging these values into the formula, we get:
π₯ = -2/ (2*1)
π₯ = -1
So the axis of symmetry is π₯ = -1.
To find the vertex, we can substitute the value of π₯ into the equation:
π¦ = (-1)^2 + 2(-1) - 2
π¦ = 1 - 2 - 2
π¦ = -3
So the vertex is (-1,-3).
To find the y-intercept, we can substitute π₯ = 0 into the equation:
π¦ = (0)^2 + 2(0) - 2
π¦ = 0 - 0 - 2
π¦ = -2
So the y-intercept is (0,-2).