Factor by grouping x^3−4x^2−4x+16
(x+4)(x+2)
(x+4)(x2−4)
(x−4)(x2−4)
(x−4)(x−2)
(x^3 - 4x^2) + (-4x + 16)
Taking out the common factor from the first two terms:
x^2(x - 4) - 4x + 16
Taking out the common factor from the last two terms:
x^2(x - 4) - 4(x - 4)
Factoring out (x - 4) from both terms:
(x - 4)(x^2 - 4) = (x - 4)(x + 2)(x - 2)
So the correct factorization is (x - 4)(x + 2)(x - 2)