What is the missing exponent that would make this equation true?
k^−5⋅ k^2/k^x=(k0)^−2
Responses
x = -5
x = -3
x = 2
x = 0
x = -3
is k^−5⋅ k^2/k^-3=(k0)^−2 true
No, the equation is not true.
k^(-5) * k^2 / k^(-3) = k^(-5 + 2 - (-3)) = k^(5 + 2 + 3) = k^10
(k^0)^(-2) = 1^(-2) = 1
Since k^10 ≠ 1, the equation is not true.
what would make it true
To make the equation true, the missing exponent would be x = 10.
k^(-5) * k^2 / k^(-3) = k^(-5 + 2 - (-3)) = k^(10)
(k^0)^(-2) = 1^(-2) = 1
Since k^(10) = 1, the equation is true.