Two weeks before an examination day, a librarian monitored the number of students who visited the library. Then they compared it with the number of visits made in an average week. Approximately 2×10^3 visits were reflected in their logbook during this two-week period, while only about 5×10^2 were reflected on an average week. How many times higher is the number of library visits before examination day compared to the library visits in an average week? Your answer should be a whole number.
To find the number of times higher, we need to divide the number of visits before examination day by the number of visits in an average week.
Number of visits before examination day = 2 × 10^3
Number of visits in an average week = 5 × 10^2
Number of times higher = (2 × 10^3) / (5 × 10^2)
This can be simplified by canceling out the common factors:
Number of times higher = (2/5) × (10^3 / 10^2)
= 2/5 × 10^(3-2)
= 2/5 × 10^1
= 2 × 10
= 20
Therefore, the number of library visits before examination day is 20 times higher compared to the library visits in an average week.
the answer has the be a whole number
I apologize for the mistake. Let's try again.
Number of visits before examination day = 2 × 10^3
Number of visits in an average week = 5 × 10^2
Number of times higher = (2 × 10^3) / (5 × 10^2)
= 2/5 × 10^(3-2)
= 2/5 × 10^1
= 2 × 10
= 20
Therefore, the number of library visits before examination day is 20 times higher compared to the library visits in an average week.
it says wrong
I apologize for the incorrect response. To find the number of times higher, we divide the number of visits before examination day by the number of visits in an average week.
Number of visits before examination day = 2 × 10^3
Number of visits in an average week = 5 × 10^2
Number of times higher = (2 × 10^3) / (5 × 10^2)
= (2/5) × (10^3 / 10^2)
= (2/5) × 10^(3-2)
= (2/5) × 10^1
= 2/5 × 10
= (2/5) × (10/1)
= 4
Therefore, the number of library visits before examination day is 4 times higher compared to the library visits in an average week.