Two triangles used in an art project are similar. The sides of the smaller triangle have lengths of 6 in., 7 in., and 12 in. The perimeter of the larger triangle is 75 in. What is the length of the shortest side of the larger triangle?(1 point)
in.
The ratio of corresponding side lengths in similar triangles is equal. Let's set up a proportion using the sides of the smaller and larger triangles.
Let x be the length of the shortest side of the larger triangle.
Using the side lengths given for the smaller triangle, the proportion is:
6/7 = x/75
Cross multiplying, we get:
6 * 75 = 7 * x
450 = 7x
Dividing both sides by 7, we find:
x = 64.29
Therefore, the length of the shortest side of the larger triangle is approximately 64.29 inches.