Answer the following questions about the molecule OCS. How many valence electrons does OCS contain. Draw a valid lewis structure
OCS (carbonyl sulfide) contains 18 valence electrons.
To draw the Lewis structure of OCS, we first need to count the total number of valence electrons. Oxygen (O) has 6 valence electrons, carbon (C) has 4 valence electrons, and sulfur (S) has 6 valence electrons. Considering there is one carbon atom, one oxygen atom, and one sulfur atom in the molecule, we have a total of (6 + 4 + 6) = 16 valence electrons.
Next, we arrange the atoms, putting the carbon in the center, and the oxygen and sulfur attached to it. As oxygen is more electronegative than sulfur, it is usually placed next to the carbon.
To fulfill the octet rule for all atoms, we need to add two more valence electrons to the structure. This brings the total number of valence electrons to 18. We can achieve this by forming a double bond between carbon and oxygen.
The Lewis structure for OCS would look like this:
O
╱ ╲
S = C
Each line in the structure represents a bond, and each bond consists of two electrons. The two bonds between carbon and sulfur and between carbon and oxygen fulfill the octet rule for carbon (4 electrons) and the octet rule for sulfur (6 electrons) and oxygen (6 electrons).
The Lewis structure of OCS satisfies the octet rule for all atoms and contains 18 valence electrons.