In which of the following sets of numbers are all the numbers solutions to 60/g> 3x5?
3,4,and 5
1,2,and 3
2,3,and 4
4,5,and 6
To find the set of numbers that are solutions to the inequality $60/g > 3x5$, we can plug in each set of numbers and see if the inequality holds true.
For the first set of numbers, plugging in $3$, $4$, and $5$, we have: \begin{align*}
60/3 &> 3(5) \\
20 &> 15 \quad \text{which is false}
\end{align*}So the first set of numbers is not a solution to the inequality.
For the second set of numbers, plugging in $1$, $2$, and $3$, we have: \begin{align*}
60/1 &> 3(5) \\
60 &> 15 \quad \text{which is true}
\end{align*}So the second set of numbers is a solution to the inequality.
For the third set of numbers, plugging in $2$, $3$, and $4$, we have: \begin{align*}
60/2 &> 3(5) \\
30 &> 15 \quad \text{which is true}
\end{align*}So the third set of numbers is a solution to the inequality.
For the fourth set of numbers, plugging in $4$, $5$, and $6$, we have: \begin{align*}
60/4 &> 3(5) \\
15 &> 15 \quad \text{which is false}
\end{align*}So the fourth set of numbers is not a solution to the inequality.
Therefore, the set of numbers that are solutions to the inequality $60/g > 3x5$ is the second set of numbers, which is $\boxed{1, 2, \text{ and } 3}$.