Write the ratios for sin~A and cos~A The triangle is not drawn to scale.
A
50
14
B
48
(1 point)
sin~A=\frac{14}{50} cos~A=\frac{48}{50}
sin~A=\frac{48}{50}, cos~A=\frac{14}{50}
sin~A=\frac{48}{14} cos~A=\frac{14}{50}
sin~A=\frac{48}{50}, cos~A=\frac{14}{48}
The correct answer is:
sin~A = 14/50, cos~A = 48/50