what is the mission exponent that would make the equation true?
k^-5 ∙ k^2/k^x = (k^0)^-2
To find the value of x that would make the equation true, let's simplify each side of the equation:
Starting with the left side:
k^-5 ∙ k^2 = k^-3 (since k^-5 ∙ k^2 = k^(-5+2) = k^-3)
Now, the right side:
(k^0)^-2 = 1^-2 = 1 (since any number raised to the power of zero is 1)
Now, let's compare both sides of the equation:
k^-3 = 1
To make k^-3 equal to 1, the exponent must be 0.
Therefore, the value of x that would make the equation true is x = 0.