NO
is dilated by a scale factor of one third
3
1
to form start overline, N, prime, O, prime, end overline
N
′
O
′
. start overline, N, O, end overline
NO
measures 1515. What is the measure of start overline, N, prime, O, prime, end overline
N
′
O
′
?
Answer
Attempt 1 out of 2
To find the measure of N′O′, we need to apply the scale factor of 1/3 to NO.
Since the scale factor is less than 1, the length of N′O′ will be smaller than the length of NO.
To find the length of N′O′, we can multiply the length of NO by the scale factor:
N′O′ = NO × scale factor
N′O′ = 1515 × 1/3
N′O′ = 505
Therefore, the measure of N′O′ is 505.