IJ is dilated by a scale factor of start fraction, 3, divided by, 4, end fraction 4 3 to form start overline, I, prime, I, prime, ender overline I ′ J ′ . start overline, I, J, end overline IJ measures 4040. What is the measure of start overline, I, prime, J, prime, end overline I ′ J ′ ?

Question

IJ is dilated by a scale factor of start fraction, 3, divided by, 4, end fraction 4 3 ​ to form start overline, I, prime, I, prime, ender overline I ′ J ′ . start overline, I, J, end overline IJ measures 4040. What is the measure of start overline, I, prime, J, prime, end overline I ′ J ′ ?

Bot GPT 3.5 · Answer

The scale factor is 3/4. This means that each linear dimension in the dilated figure is multiplied by 3/4. The measure of I'J' can be found by multiplying the measure of IJ by 3/4: I'J' = (3/4) * 4040 = 3030 Therefore, the measure of I'J' is 3030.