Jerome leaves home, walks two blocks east, one block north, then two blocks west. If each block is 300 feet in length, what is Jerome's distance traveled and final displacement?
The distance traveled by Jerome can be calculated by adding the distances traveled in each direction.
He walks two blocks east, which is a distance of 2 * 300 feet = <<2*300=600>>600 feet.
He then walks one block north, a distance of 1 * 300 feet = <<1*300=300>>300 feet.
Finally, he walks two blocks west, which is a distance of 2 * 300 feet = <<2*300=600>>600 feet.
So in total, Jerome travels a distance of 600 + 300 + 600 = <<600+300+600=1500>>1500 feet.
The final displacement is the straight-line distance from his initial position to his final position. The two blocks east and two blocks west cancel each other out in terms of horizontal movement.
His northward movement is one block, which is a displacement of 1 * 300 feet = <<1*300=300>>300 feet.
Therefore, Jerome's final displacement is 300 feet north.