A golfer takes two putts to get his ball into the hole once he is on the green. The first putt displaces the ball
6.30 m [E], and the second, 5.40 m [N]. What displacement would have been needed to get the ball into the
hole on the first putt? 8.30 m {N 49º]
To find the displacement needed to get the ball into the hole on the first putt, we can calculate the resultant displacement of the two putts.
Let's break down the displacements into their horizontal and vertical components.
For the first putt:
Horizontal component = 6.30 m
Vertical component = 0 m (since it's straight east)
For the second putt:
Horizontal component = 0 m (since it's straight north)
Vertical component = 5.40 m
To find the resultant displacement, we can use the Pythagorean theorem:
Resultant displacement = √((6.30^2) + (5.40^2))
Resultant displacement = √(39.69 + 29.16)
Resultant displacement = √68.85
Resultant displacement ≈ 8.30 m
Therefore, the displacement needed to get the ball into the hole on the first putt would have been approximately 8.30 m.