The solubility in acetonitrile of an organic compound A is measured and found to be 4.82 g/L at 25 0C. Calculate the volume of a saturated solution of A in acetonitrile that would contain 267 mg of A at this temperature. Round to 3 sig figs.
To solve this problem, we need to use the relationship between solubility, mass, and volume.
Given:
Solubility of A in acetonitrile = 4.82 g/L
Mass of A = 267 mg = 0.267 g
First, we need to calculate the volume of the saturated solution that would contain 1 g of A using the solubility. This will give us the conversion factor for solving our main problem.
Volume of 1 g of A = 1 g / 4.82 g/L = 0.207 L/g
Now, we can use this conversion factor to calculate the volume for 0.267 g of A:
Volume of 0.267 g of A = 0.267 g × ( 0.207 L/g) = 0.055 L
Rounded to 3 significant figures, the volume of the saturated solution containing 267 mg of A is approximately 0.055 L.