The quadratic equation 6x^2 -x-15=0 in factored form is. Select the correct answer from the following.

a) (6x+5) (2x -3) =0
b) (6x+5) (x-1) =0
c) (3x-5) (2x +3) =0
d) (3x-5) (2x -3) =0
Which results in the solutions x, select the correct answer from the following.
a) 5
b) -5
c) -6/5
d) 5/3
and x =
a) -3/2
b) 3
c) -3
d) 1

To solve the quadratic equation 6x^2 - x - 15 = 0, we need to factorize it.

To factorize the quadratic equation, we need to find two numbers whose product is equal to the product of the coefficient of x^2 (6) and the constant term (-15), and whose sum is equal to the coefficient of x (-1).

The two numbers that satisfy these conditions are 5 and -3.

So, the factored form of the quadratic equation is (6x + 5)(x - 3) = 0

Therefore, the correct answer for the factored form is (a) (6x + 5)(x - 3) = 0

To find the solutions x that result from this factored form, we set each factor equal to zero and solve for x.

Setting 6x + 5 = 0, we get x = -5/6

Setting x - 3 = 0, we get x = 3

Therefore, the correct answers for the solutions x are (c) -5/6 and (b) 3.

Do you mean the correct answer for the factor form is a) (6x+5) (2x-3) =0. Not the answer you gave which is (6x+5) (x-3) =0, where you did not include the 2.

You are correct, I apologize for the error. The correct factored form of the quadratic equation 6x^2 - x - 15 = 0 is (6x + 5)(2x - 3) = 0. Thank you for catching that mistake.