you have a bottle which 236 coins,consisting only of 20c pieces and 50c pieces.if there are three time as many 20c pieces,determine the total amount of money in the bottle
Let's assume there are x 20c pieces and y 50c pieces in the bottle.
Given that there are three times as many 20c pieces as 50c pieces, we can write the equation:
x = 3y
Since the total number of coins in the bottle is 236, we have:
x + y = 236
Replacing the value of x in terms of y from the first equation into the second equation:
3y + y = 236
4y = 236
y = 59
Substituting the value of y back into the equation x = 3y:
x = 3(59)
x = 177
So, there are 177 20c pieces and 59 50c pieces in the bottle.
To calculate the total amount of money in the bottle, we multiply the number of each coin by its value:
Total amount = (Number of 20c pieces * Value of 20c) + (Number of 50c pieces * Value of 50c)
Total amount = (177 * 20c) + (59 * 50c)
Total amount = 3540c + 2950c
Total amount = 6490c
Therefore, the total amount of money in the bottle is 6490 cents, or $64.90.