Two supplementary angles have measures m∠ABC=105° and m∠CBD=(3x−24)° . What is the equation to solve for x ? (1 point) (3x−24)°+°= °

m∠ABC + m∠CBD = 180° (since supplementary angles add up to 180°)

105° + (3x - 24)° = 180°

Simplifying the equation, we have:

3x - 24 + 105 = 180

3x + 81 = 180

3x = 180 - 81

3x = 99

Dividing both sides of the equation by 3, we get:

x = 33

Therefore, the equation to solve for x is:

(3x - 24)° + ° = °

write it out with no blanks

105° + (3x - 24)° = 180°

Two angles are supplementary with measures m∠ACB=4x° and m∠BCD=(6x+50)°. What is the measure of ∠ACB?(1 point) m∠ACB=

m∠ACB = 4x°

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