A refrigerator can convert 600g of water at 50 degree to ice at 0 degree in 3.5 hours. Find the average rate of heat absorbed from water in watt.
To find the average rate of heat absorbed from water, we need to calculate the amount of heat absorbed and divide it by the time it took.
First, let's calculate the amount of heat absorbed by the water. The specific heat capacity of water is 4.18 J/g•°C.
The temperature change the water goes through is:
50°C - 0°C = 50°C
The amount of heat absorbed is given by the equation:
Q = mass * specific heat capacity * temperature change
Q = 600g * 4.18 J/g•°C * 50°C
Q = 125400 J
Next, let's convert the time to seconds:
3.5 hours * 60 minutes/hour * 60 seconds/minute = 12600 seconds
Finally, let's calculate the average rate of heat absorbed:
Average rate = Q / t
Average rate = 125400 J / 12600 s
Average rate ≈ 9.95 J/s
Therefore, the average rate of heat absorbed from the water is approximately 9.95 watts.