7)
Pat shows that 1612=16−−√
. What is one possible way Pat could have shown this correctly?
(1 point)
Responses
1612=(8⋅8)12=812⋅812=812+12=81=8=16−−√
16 raised to the 1 half power is equal to open paren 8 times 8 close paren raised to the 1 half power is equal to 8 raised to the 1 half power times 8 raised to the 1 half power is equal to 8 raised to the 1 half plus 1 half power is equal to 8 to the 1th power is equal to 8 is equal to square root of 16
1612=(4⋅4)12=412⋅412=412⋅12=41=4=16−−√
16 raised to the 1 half power is equal to open paren 4 times 4 close paren raised to the 1 half power is equal to 4 raised to the 1 half power times 4 raised to the 1 half power is equal to 4 raised to the 1 half times 1 half power is equal to 4 to the 1th power is equal to 4 is equal to square root of 16
1612=(8+8)12=812⋅812=812⋅+12=81=8=16−−√
16 raised to the 1 half power is equal to open paren 8 plus 8 close paren raised to the 1 half power is equal to 8 raised to the 1 half power times 8 raised to the 1 half power is equal to 8 raised to the the fraction with numerator 1 and denominator 2 times plus 1 half power is equal to 8 to the 1th power is equal to 8 is equal to square root of 16
1612=(4⋅4)12=412⋅412=412+12=41=4=16−−√
16 raised to the 1 half power is equal to open paren 4 times 4 close paren raised to the 1 half power is equal to 4 raised to the 1 half power times 4 raised to the 1 half power is equal to 4 raised to the 1 half plus 1 half power is equal to 4 to the 1th power is equal to 4 is equal to square root of 16
1612=(4+4)12=412⋅412=412⋅+12=41=4=16−−√