7. A falling stone takes 0.30 s to pass a window 2.1 m long. From what height was the stone
dropped?
We can use the formula for the distance fallen by an object:
d = 1/2 * g * t^2
where:
d = distance fallen (unknown)
g = acceleration due to gravity (unknown)
t = time taken to fall (0.30 s)
To find the height from which the stone was dropped, we need to solve for d. Rearranging the formula, we have:
d = 1/2 * g * t^2
d = (1/2) * (9.8 m/s^2) * (0.30 s)^2
d = (1/2) * (9.8 m/s^2) * 0.09 s^2
d = (0.5) * (9.8 m/s^2) * 0.09 s^2
d = 0.441 m
Therefore, the stone was dropped from a height of 0.441 meters.