a block rests on a horizontal surface. The normal force is 20N. The coefficient of static friction between the block and the surface is 0,40 and the coefficient of dynamic is 0,20.
what is the magnitude of the frictional force exerted on the block while the block is at rest?
The magnitude of the frictional force exerted on the block while the block is at rest can be calculated using the equation:
Frictional force = coefficient of static friction * normal force
Given:
Coefficient of static friction = 0.40
Normal force = 20N
Frictional force = 0.40 * 20N = 8N
Therefore, the magnitude of the frictional force exerted on the block while the block is at rest is 8N.