The perimeter of a rectangle is 192 ft. The ratio of its length to its width is 7 : 5. What are the dimensions of the rectangle?
Question 2 options:
60 ft by 36 ft
56 ft by 40 ft
48 ft by 48 ft
44 ft by 52 ft
Let's assume the length of the rectangle as 7x and the width as 5x, where x is a common ratio factor.
The perimeter of the rectangle is given by 2(length + width):
2(7x + 5x) = 192 ft
2(12x) = 192 ft
24x = 192 ft
x = 192 ft / 24
x = 8 ft
So, the length of the rectangle is 7x = 7(8 ft) = 56 ft, and the width is 5x = 5(8 ft) = 40 ft.
Therefore, the dimensions of the rectangle are 56 ft by 40 ft.