11. A 3 stage rocket is launched vertically upwards. The data for each stage is as follows:
STAGE ACCELERATION /TIME
1 15m/s 2 60s
2 20m/s 2 40s
3 l0m/s 2 80s
Determine: (b) the height of the rocket at the
end of the third stage.
To find the height of the rocket at the end of the third stage, we need to calculate the distance traveled by each stage and then sum them up.
For the first stage:
Using the formula for distance traveled during acceleration:
distance = (1/2) * acceleration * time^2
distance = (1/2) * 15 * (60^2) = 27,000 meters
For the second stage:
distance = (1/2) * 20 * (40^2) = 16,000 meters
For the third stage:
distance = (1/2) * 10 * (80^2) = 32,000 meters
The total distance traveled by the rocket at the end of the third stage is:
27,000 + 16,000 + 32,000 = 75,000 meters
Therefore, the height of the rocket at the end of the third stage is 75,000 meters.