Find the slope of a line perpendicular to the line whose equation is 9, x, plus, 3, y, equals, 369x+3y=36.
To find the slope of a line perpendicular to the given line, we first need to find the slope of the given line.
To do this, we can rearrange the equation 369x + 3y = 36 into slope-intercept form (y = mx + b), where m is the slope.
First, subtract 369x from both sides of the equation:
3y = -369x + 36
Next, divide both sides of the equation by 3:
y = (-369/3)x + 12
Now we can see that the slope of the given line is -369/3.
The slope of a line perpendicular to this line is the negative reciprocal of this slope.
The negative reciprocal of -369/3 is 3/369, which simplifies to 1/123.
Therefore, the slope of the line perpendicular to the given line is 1/123.