Find the slope of a line perpendicular to the line whose equation is 5, x, plus, y, equals, minus, 45x+y=−4
To find the slope of a line perpendicular to a given line, we need to find the negative reciprocal of the slope of the given line.
The given line has the equation -45x + y = -4.
Rewriting the equation in slope-intercept form (y = mx + b) by isolating y, we get:
y = 45x - 4
In this equation, the coefficient of x is the slope of the line, which is 45.
The negative reciprocal of 45 is -1/45.
Therefore, the slope of a line perpendicular to the given line is -1/45.