Find the slope of a line perpendicular to the line whose equation is 3, x, minus, 6, y, equals, minus, 723x−6y=−72
To find the slope of a line perpendicular to this line, we need to find the slope of the given line first.
The equation of the given line is 723x - 6y = -72.
To find the slope of the given line, we need to rearrange this equation into slope-intercept form, y = mx + b, where m is the slope.
Rearranging, we have:
-6y = -723x - 72
Dividing both sides by -6, we get:
y = (723/6)x + 12
Comparing this equation to y = mx + b, we see that the slope (m) of the given line is 723/6.
To find the slope of a line perpendicular to this line, we need to take the negative reciprocal of the slope.
The negative reciprocal of 723/6 is -6/723.
Therefore, the slope of a line perpendicular to the given line is -6/723.