Find the slope of a line perpendicular to the line whose equation is 6, x, plus, y, equals, minus, 56x+y=−5
To find the slope of a line perpendicular to a given line, we need to find the negative reciprocal of the slope of the given line.
The equation of the given line is 6x + y = -56x + y = -5
To put it in slope-intercept form (y = mx + b), we need to isolate y:
y = -56x - 6x - 5 → y = -62x - 5
The slope of the given line is -62.
The slope of a line perpendicular to this line will be the negative reciprocal of -62, which is 1/62.
Therefore, the slope of a line perpendicular to the given line is 1/62.