Find the slope of a line perpendicular to the line whose equation is 3, x, plus, y, equals, 83x+y=8
To find the slope of the line whose equation is perpendicular to the given line, we need to first determine the slope of the given line.
The equation of the line is 83x + y = 8. Let's rewrite this equation in slope-intercept form (y = mx + b), where m is the slope:
y = -83x + 8
Comparing this to y = mx + b, we can see that the slope of the given line is -83.
For lines that are perpendicular to each other, the slopes are negative reciprocals of each other. Thus, the slope of the line perpendicular to the given line would be the negative reciprocal of -83.
The negative reciprocal of -83 is 1/83.
Therefore, the slope of the line perpendicular to the line whose equation is 83x + y = 8 is 1/83.