Two resistors with resistance 100 Ω and 4 700 Ω, respectively, are connected in parallel in a
circuit. The total resistance of the circuit is:
To find the total resistance of resistors connected in parallel, we use the formula:
1/RT = 1/R1 + 1/R2 + 1/R3 + ...
Where RT is the total resistance and R1, R2, R3, ... are the individual resistances.
In this case, we have two resistors connected in parallel with resistances of 100 Ω and 4700 Ω respectively. Plugging these values into the formula, we get:
1/RT = 1/100 + 1/4700
To simplify this equation, we can take the LCD (least common denominator) of 100 and 4700, which is 100.
1/RT = 1/100 + 1/4700 * 100/100
1/RT = 1/100 + 100/470000
1/RT = (4700 + 100)/470000
1/RT = 4800/470000
To isolate RT, we can take the reciprocal of both sides:
RT/1 = 470000/4800
RT = 470000/4800
Simplifying this expression, we get:
RT = 97.92 Ω
Therefore, the total resistance of the circuit is approximately 97.92 Ω.