Given point A (2, 4) on the triangle in Quadrant I, where is the new point of the triangle is rotated 90 degrees counterclockwise?
To rotate a point 90 degrees counterclockwise, we can swap the x and y coordinates and then negate the new x-coordinate.
The given point A is (2, 4). Swapping the x and y coordinates gives us the point (4, 2). Negating the new x-coordinate gives us the final point after rotation, which is (-4, 2).
Therefore, the new point of the triangle after rotating 90 degrees counterclockwise is (-4, 2).