14. A boy is riding a bicycle at a velocity of 4 m/s. The bieycle's whel's have a diameter of 0.8m and 40 revolutions.
c) what is the angular acceleration of a point on the rim of the wheel?
To find the angular acceleration of a point on the rim of the wheel, we first need to find the angular velocity.
Angular velocity is defined as the change in angular displacement divided by the change in time.
Given that the wheels have a diameter of 0.8m and the boy completes 40 revolutions, we can calculate the angular displacement.
One revolution is equal to the circumference of the wheel, which is given by C = πd, where d is the diameter of the wheel.
So, the angular displacement for 40 revolutions is given by θ = 40(2π), where 2π represents one revolution.
Next, we need to find the time taken to complete 40 revolutions.
The time taken is equal to the distance traveled divided by the velocity, which is given by t = (40 revolutions)(C)/(4 m/s).
Substituting C = πd and d = 0.8m, we can calculate the time taken to complete 40 revolutions.
Finally, we can calculate the angular velocity by dividing the angular displacement by the time taken.
Angular velocity = θ/t.
Once we have the angular velocity, we can find the angular acceleration.
Angular acceleration is defined as the change in angular velocity divided by the change in time.
However, in this case, the velocity remains constant, so the angular acceleration is 0.
Therefore, the angular acceleration of a point on the rim of the wheel is 0.