What is the ratio of translational and rotational kinetic energy of solid rod
The ratio of translational and rotational kinetic energy of a solid rod depends on the axis of rotation and the distance of the axis of rotation from the center of mass of the rod.
If the axis of rotation is at the center of mass of the rod, the ratio of translational and rotational kinetic energy is 1:1. In this case, all of the kinetic energy is in the form of translational motion.
If the axis of rotation is parallel to the rod but not passing through the center of mass, the ratio of translational and rotational kinetic energy will be different. The rotational kinetic energy will be higher than the translational kinetic energy.
The actual ratio of translational and rotational kinetic energy can be calculated using the formulas for translational and rotational kinetic energy:
Translational kinetic energy = (1/2) * m * v^2
Rotational kinetic energy = (1/2) * I * ω^2
Where m is the mass of the rod, v is the velocity of the rod, I is the moment of inertia of the rod about the axis of rotation, and ω is the angular velocity of the rod.
The ratio of translational and rotational kinetic energy can be calculated as:
Ratio = (Translational kinetic energy) / (Rotational kinetic energy)
Note that the moment of inertia of the rod about an axis that is parallel but not passing through the center of mass can be complicated to calculate. It depends on the mass distribution of the rod and the distance of the axis of rotation from the center of mass.
In summary, the ratio of translational and rotational kinetic energy of a solid rod depends on the axis of rotation and the distance of the axis of rotation from the center of mass of the rod.