Quadrilateral ABCD has vertices

4(3, 9), B(6, 0), C(3, -6), and D(-3, 0).

Quadrilateral ABCD is dilated by a scale factor
of
¿ with the origin as the center of dilation

What are the new coordinates of the vertices of

A'B'CD?

A A (1, 3), B (2, 0), C(1, -2), D'(-1, 0)

B A(1, 3), B'(-2, 0), C'(-1, -2), D'(-1, 0)

C A'(1, 3), B'(2, 0), C(-1, 2), D'(-1, 0)

A71, 3), B'(-2, 0), C(1, -2), D' (1, 0)

The correct answer is option B: A (1, 3), B'(-2, 0), C'(-1, -2), D'(-1, 0).