how much would the force of a 70 kg person would be on earth
The force experienced by a 70 kg person on Earth can be calculated using the equation F = m * g, where F is the force, m is the mass, and g is the acceleration due to gravity. On Earth, the value of g is approximately 9.8 m/s^2.
So, the force on a 70 kg person on Earth would be:
F = 70 kg * 9.8 m/s^2
F = 686 N
Therefore, the force experienced by a 70 kg person on Earth is approximately 686 Newtons.