two angles are supplementary, and have measures
m<QRS=(x+ 40)°
And
m<SRT= x°
What is the measure of m<QRS
The measure of angle QRS can be found by adding the measures of angles QRS and SRT and setting it equal to 180 degrees, since supplementary angles add up to 180 degrees.
m<QRS + m<SRT = 180 degrees
(x + 40) + x = 180
2x + 40 = 180
2x = 140
x = 70
Therefore, the measure of angle QRS is:
m<QRS = x + 40 = 70 + 40 = 110 degrees
Three angles measures add to 180° and have the following measures: m<ACB = (x+ 15)°
m<BCD= (x+ 48)°
And
m<DCE= 13°
What is the measure of?< BCD.
To find the measure of angle BCD, we need to set up an equation using the fact that the sum of the angle measures is equal to 180 degrees.
m<ACB + m<BCD + m<DCE = 180
(x + 15) + (x + 48) + 13 = 180
2x + 76 + 13 = 180
2x + 89 = 180
2x = 91
x = 45.5
Therefore, the measure of angle BCD is:
m<BCD = x + 48 = 45.5 + 48 = 93.5 degrees
Soo 100?
Apologies for the mistake in my previous response. Let's recalculate the measure of angle BCD correctly:
m<ACB + m<BCD + m<DCE = 180
(x + 15) + (x + 48) + 13 = 180
2x + 76 + 13 = 180
2x + 89 = 180
2x = 91
x = 45.5
To find the measure of angle BCD:
m<BCD = x + 48
= 45.5 + 48
= 93.5 degrees
Therefore, the correct measure of angle BCD is 93.5 degrees.
The answer was 100
Apologies for the confusion. Let's recheck the calculations:
m<ACB + m<BCD + m<DCE = 180
(x + 15) + (x + 48) + 13 = 180
2x + 76 + 13 = 180
2x + 89 = 180
2x = 91
x = 45.5
To find the measure of angle BCD:
m<BCD = x + 48
= 45.5 + 48
= 93.5 degrees
I apologize for my earlier incorrect response. The correct measure of angle BCD is indeed 93.5 degrees, not 100 degrees.