An object of 2.0cm high is placed 10cm from a converging mirror of focal length 5cm what is the height of the image formed
To find the height of the image formed by the converging mirror, we can use the mirror equation:
1/f = 1/do + 1/di
Where:
- f is the focal length of the mirror
- do is the object distance (the distance between the object and the mirror)
- di is the image distance (the distance between the image and the mirror)
In this case, the object distance, do, is 10 cm and the focal length, f, is 5 cm. Plugging these values into the mirror equation:
1/5 = 1/10 + 1/di
Solving for di:
1/di = 1/5 - 1/10
1/di = (2 - 1)/10
1/di = 1/10
di = 10 cm
Now that we have the image distance, di, we can use the magnification equation to find the height of the image:
magnification = height of image / height of object
The magnification equation is given by:
magnification = -(di/do)
In this case, di is 10 cm and do is 10 cm, so:
magnification = -(10/10) = -1
Since the magnification is negative, the image is inverted. Since the height of the object is 2.0 cm, the height of the image will also be 2.0 cm but inverted. So, the height of the image formed is 2.0 cm.