Given point A (2, 4) on the triangle Quadrant I, where is the new point if the triangle is rotated 270 degrees counterclockwise?
(1 point)
• (4, -2)
• (-2, -4)
• (-4, -2)
0 (-4, 2)
To rotate a point 270 degrees counterclockwise, we can use the following formula:
x' = -y
y' = x
Let's apply this formula to point A (2, 4):
x' = -4 = -y
y' = 2 = x
Therefore, the new point is (-4, 2).
So, the correct answer is 0) (-4, 2).