A box has volume given by the trinomial x^3 + 5x^2 - 24x. What are the possible dimensions of the box? use factoring.
(1 point)
A. x, x - 3, and x + 8
B. x, x + 3, and x + 8
C. x, x - 3, and x - 8
D. x, x + 3, and x - 8
The possible dimensions of the box correspond to the factors of the trinomial x^3 + 5x^2 - 24x.
We can factor out an x from each term to get x(x^2 + 5x - 24).
Next, we need to factor the quadratic x^2 + 5x - 24. This can be factored as (x + 8)(x - 3).
So the trinomial x^3 + 5x^2 - 24x can be factored as x(x + 8)(x - 3).
Therefore, the possible dimensions of the box are x, x + 8, and x - 3.
The correct answer is:
A. x, x - 3, and x + 8