two buses leave housten at the same time and travel in opposite directions. one buse averages 55mi/h and the other 4.5mi/h. when will they be 400 mi apart.
this probably is the easiest thing..and also could u write it out for me so when i do it i can actually get it...thnx
is that 45 mi/h or 4.5 mi/h
45mi/h
1.6 miles x 60 min.
96 miles per hour
400 / 96 = 4hours &10 min.
To solve this problem, we can use the formula:
Distance = Speed x Time
Let's break down the problem step by step and write out the solution:
1. The two buses are traveling in opposite directions, so we need to consider their combined speed. To find the combined speed, we add the speeds of the two buses:
Combined speed = Speed of first bus + Speed of second bus
Given that the first bus averages 55 mi/h and the second bus averages 4.5 mi/h, the combined speed would be:
Combined speed = 55 mi/h + 4.5 mi/h
2. Now, we can use the formula Distance = Speed x Time to find when the buses will be 400 miles apart. We'll let "t" represent the time it takes.
Distance = Combined speed x Time
400 miles = (55 mi/h + 4.5 mi/h) x t
3. Simplify the equation:
400 miles = 59.5 mi/h x t
4. To solve for "t", divide both sides of the equation by 59.5 mi/h:
t = 400 miles ÷ 59.5 mi/h
5. Calculate the value of "t":
t ≈ 6.72 hours
Therefore, the buses will be 400 miles apart after approximately 6.72 hours.